Q. Considering that the angles of a regular pentagon are 108º, why is cyclopentane not planar?

Question ID: 8391
  1. all the carbons are sp2 hybridized, so there is considerable angle strain.
  2. The C-C bonds are formed by overlap of p-orbitals, so the 90º angle results in large angle strain.
  3. The cyclic overlap of bonding orbitals results in anti-aromaticity destabilization
  4. The five C-C bonds have eclipsing strain


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