Q. 10 years ago the age of a family of 5 members was 38 years. Now 2 new members joined, whose age difference is 8 years. If the present average age of the family is the same as it was 10 years ago, what is the age (in years) of the new younger member?
Question ID: 38436
9
15
10
None of these
1
Answer/सही जवाब: (1)
Explanation/विवरण: Total age of 2 new members = 38 × 7 – 48 × 5 = 26
Difference = 8 years ∴ Age = 17, 9