Advance Maths Questions for SSC CGL Set 2
Dear Students, here in
Advance Maths Questions for SSC CGL Set 2 we will discus 10 previous year asked questions in SSC CGL. Solve these questions.
Q.n : 1 - What is the value of 143 + 163 + 183 + … + 303?
143 + 163 + 183 + … + 303 का मान क्या है?
Options:
1) 134576
2) 120212
3) 115624
4) 111672
Q.n : 2 - What is the value of √(4600 + √(540 + √(1280 + √(250 + √36))))
√(4600 + √(540 + √(1280 + √(250 + √36)))) का मान क्या है?
Options:
1) 69
2) 68
3) 70
4) 72
Q.n : 3 - If x + y + z = 0, then what is the value of (3y2 + x2 + z2)/(2y2 – xz)?
यदि x + y + z = 0 हो, तो (3y2 + x2 + z2)/(2y2 – xz) का मान क्या है?
Options:
1) 2
2) 1
3) 3/2
4) 5/3
Q.n : 4 - If P = 7 + 4√3 and PQ = 1, then what is the value of 1/P2 + 1/Q2?
यदि P = 7 + 4√3 तथा PQ = 1 हैं, तो 1/P2 + 1/Q2 का मान क्या है?
Options:
1) 196
2) 194
3) 206
4) 182
Q.n : 5 - If a3 + 3a2 + 9a = 1, then what is the value of a3 + (3/a)?
यदि a3 + 3a2 + 9a = 1 हो, तो a3 + (3/a) का मान क्या है?
Options:
1) 31
2) 26
3) 28
4) 24
Q.n : 6 - x, y and z are real numbers. If x3 + y3 + z3 = 13,x + y + z = 1 and xyz = 1, then what is the value of xy + yz + zx?
x, y तथा z वास्तविक संख्याएँ हैं। यदि x3 + y3 + z3 = 13, x + y + z = 1 तथा xyz = 1 हैं, तो xy + yz + zx का मान क्या है?
Options:
1) – 1
2) 1
3) 3
4) – 3
Q.n : 7 - If (a + b)/c = 6/5 and (b + c)/a = 9/2, then what is the value of (a + c)/b?
यदि (a + b)/c = 6/5 तथा (b + c)/a = 9/2 हैं, तो (a + c)/b का मान क्या है?
Options:
1) 9/5
2) 11/7
3) 7/11
4) 7/4
Q.n : 8 - If x3 + y3 + z3 = 3(1 + xyz), P = y + z – x, Q = z + x – y and R = x + y – z, then what is the value of P3 + Q3 + R3– 3PQR?
यदि x3 + y3 + z3 = 3(1 + xyz), P = y + z – x, Q = z + x – y तथा R = x + y – z हैं, तो P3 + Q3 + R3– 3PQR का मान क्या है?
Options:
1) 9
2) 8
3) 12
4) 6
Q.n : 9 - If x1x2x3 = 4(4 + x1 + x2 + x3), then what is the value of [1/(2 + x1)] + [1/(2 + x2)] + [1/(2 + x3)]?
यदि x1x2x3 = 4(4 + x1 + x2 + x3)हो, तो[1/(2 + x1)] + [1/(2 + x2)] + [1/(2 + x3)] का मान क्या है?
Options:
1) 1
2) 1/2
3) 2
4) 1/3
Q.n : 10 - If α and β are the roots of equation x2 – x + 1 = 0, then which equation will have roots α3 and β3?
यदि α तथा β समीकरण x2 – x + 1 = 0 के मूल हैं, तो किस समीकरण के मूल α3 तथा β3 होंगे?
Options:
1) x2 + 2x + 1 = 0
2) x2 – 2x – 1 = 0
3) x2 + 3x – 1 = 0
4) x2 – 3x + 1 = 0
Solution
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Ans/Solution in comment box.
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